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(B) The equivalent weight of an element is defined as the mass of the element that combines with $1 \ g$ of hydrogen or $8 \ g$ of oxygen or $35.5 \ g

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$20$

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(B) The equivalent weight of an element is defined as the mass of the element that combines with $1 \ g$ of hydrogen or $8 \ g$ of oxygen or $35.5 \ g$ of chlorine or its equivalent mass of bromine.Given that $1 \ g$ of hydrogen combines with $80 \ g$ of bromine,the equivalent weight of bromine is $80 \ g$.We are given that $4 \ g$ of bromine combines with $1 \ g$ of calcium.Since $80 \ g$ of bromine is the equivalent weight of bromine,the amount of calcium that combines with $80 \ g$ of bromine will be its equivalent weight.Equivalent weight of calcium $= \frac{1 \ g 	ext{ of } Ca}{4 \ g 	ext{ of } Br} 	imes 80 \ g 	ext{ of } Br = 20 \ g$.

One gram of hydrogen is found to combine with $80 \ g$ of bromine. One gram of calcium (valency $= 2$) combines with $4 \ g$ of bromine. The equivalent weight of calcium is:

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