One litre of water contains 10^{-7} mole of | vedclass

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(A) The density of water is $1 \ g/mL$,so $1 \ litre$ of water weighs $1000 \ g$.The number of moles of water in $1 \ litre$ is $n = \frac{1000 \ g}{1

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$1.8 	imes 10^{-7} \%$

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(A) The density of water is $1 \ g/mL$,so $1 \ litre$ of water weighs $1000 \ g$.The number of moles of water in $1 \ litre$ is $n = \frac{1000 \ g}{18 \ g/mol} = 55.56 \ mol$.The concentration of $H^+$ ions is $[H^+] = 10^{-7} \ mol/L$.The degree of ionization $(\alpha)$ is defined as the ratio of the number of moles ionized to the total number of moles.$\alpha = \frac{[H^+]}{[H_2O]} = \frac{10^{-7}}{55.56} = 1.8 	imes 10^{-9}$.To express this as a percentage: $\alpha \% = (1.8 	imes 10^{-9}) 	imes 100 = 1.8 	imes 10^{-7} \%$.

One litre of water contains $10^{-7} \ mole$ of hydrogen ions. The degree of ionization in water will be:

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