One mole of $P_4$ reacts with $8$ moles of $SOCl_2$ to give $4$ moles of $A$,$x$ moles of $SO_2$ and $2$ moles of $B$. $A$,$B$ and $x$ respectively are

  • A
    $PCl_3$,$S_2Cl_2$ and $4$
  • B
    $POCl_3$,$S_2Cl_2$ and $4$
  • C
    $PCl_3$,$S_2Cl_2$ and $2$
  • D
    $POCl_3$,$S_2Cl_2$ and $2$

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$2C_{(s)} + O_{2(g)} \rightarrow 2CO_{(g)}$
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In the reaction,$4NH_{3(g)} + 5O_{2(g)} \to 4NO_{(g)} + 6H_{2}O_{(g)}$,when $1 \ mole$ of ammonia and $1 \ mole$ of $O_{2}$ are made to react to completion:

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For a given unbalanced reaction, $MnO_2 + HCl \rightarrow MnCl_2 + H_2O + Cl_2$, which is the limiting reagent if the initial amount for each reactant is $100 \ g$? [Molar masses: $MnO_2 = 86.9 \ g/mol$; $HCl = 36.5 \ g/mol$]

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