(C) For the association reaction $nA \rightleftharpoons (A)_n$,let the degree of association be $x$.Initial moles: $A = 1$,$(A)_n = 0$.Moles at equili

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(C) For the association reaction $nA \rightleftharpoons (A)_n$,let the degree of association be $x$.Initial moles: $A = 1$,$(A)_n = 0$.Moles at equilibrium: $A = 1 - x$,$(A)_n = \frac{x}{n}$.Total moles at equilibrium = $(1 - x) + \frac{x}{n}$.The Van't Hoff factor $i$ is defined as the ratio of total moles of particles after association to the initial moles of solute.$i = \frac{1 - x + \frac{x}{n}}{1} = 1 - x + \frac{x}{n}$.

Class 12 Chemistry Solutions Abnormal molecular mass

Easy

One mole of a solute $A$ is dissolved in a given volume of a solvent. The association of the solute takes place according to $nA \rightleftharpoons (A)_n$. The Van't Hoff factor $i$ is expressed as:

A
$i = 1 - x$
B
$i = 1 + \frac{x}{n}$
C
$i = 1 - x + \frac{x}{n}$
D
$i = 1$

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Abnormal molecular mass

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One mole of a solute $A$ is dissolved in a given volume of a solvent. The association of the solute takes place according to $nA \rightleftharpoons (A)_n$. The Van't Hoff factor $i$ is expressed as:

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The observed and calculated molecular weights of calcium nitrate are $65.6$ and $164$ respectively. The degree of dissociation of calcium nitrate is .......... $\%$.

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