(D) The oxidation of an aldehyde to a carboxylic acid is represented by the equation: $RCHO + 0.5 O_2 \to RCOOH$ From the stoichiometry of the reactio

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(D) The oxidation of an aldehyde to a carboxylic acid is represented by the equation: $RCHO + 0.5 O_2 \to RCOOH$ From the stoichiometry of the reaction,$1$ mole of aldehyde requires $0.5$ mole of oxygen to produce $1$ mole of the corresponding carboxylic acid. Therefore,the compound is an aldehyde.