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(D) The reaction involves a Grignard reagent $(C_6H_{11}MgBr)$ and an amine $(C_6H_{11}NH_2)$.Grignard reagents are strong bases and react with compou

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Cyclohexane

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(D) The reaction involves a Grignard reagent $(C_6H_{11}MgBr)$ and an amine $(C_6H_{11}NH_2)$.Grignard reagents are strong bases and react with compounds containing active hydrogen atoms (like the $N-H$ bond in amines).The reaction proceeds as follows:$C_6H_{11}MgBr + C_6H_{11}NH_2 \rightarrow C_6H_{12} + C_6H_{11}NHMgBr$Here, the Grignard reagent abstracts a proton from the amine to form cyclohexane $(C_6H_{12})$ and a magnesium amide salt.Therefore, one of the products formed is cyclohexane.

One of the products formed in the following reaction is:
$C_6H_{11}MgBr + C_6H_{11}NH_2 \rightarrow ?$

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One of the products formed in the following reaction is: $C_6H_{11}MgBr + C_6H_{11}NH_2 \rightarrow ?$