One side of a square is increased by 30 %. To | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the side of the square be $x$.Initially,the area of the square is $A = x^2$.After increasing one side by $30 \%$,the new length is $x + 0.3x =

Vedclass · Accepted Answer

$23 \frac{1}{13} \%$

Vedclass · Answer

(A) Let the side of the square be $x$.Initially,the area of the square is $A = x^2$.After increasing one side by $30 \%$,the new length is $x + 0.3x = 1.3x$.Let the other side be $y$ such that the area remains $x^2$.So,$1.3x 	imes y = x^2$.$y = \frac{x^2}{1.3x} = \frac{x}{1.3} = \frac{10x}{13}$.The decrease in the other side is $x - \frac{10x}{13} = \frac{3x}{13}$.The percentage decrease is $\left( \frac{3x/13}{x} ight) 	imes 100 = \frac{300}{13} \% = 23 \frac{1}{13} \%$.

One side of a square is increased by $30 \%$. To maintain the same area,the other side will have to be decreased by:

Similar Questions

The value of a machine is $Rs$ $6250$. It decreases by $10 \%$ during the first year,$20 \%$ during the second year,and $30 \%$ during the third year. What will be the value of the machine after $3$ years?

$1200$ boys and $650$ girls appeared in an examination. If $70 \%$ of boys and $40 \%$ of girls failed,find the approximate percentage of passed students.

If the income of $R$ is $30 \%$ more than the income of $Q$ and the income of $Q$ is $20 \%$ more than the income of $P$,then the income of $R$ is how much percent more than the income of $P$ (in $\%$)?

The strength of a school increases and decreases in every alternate year by $10 \%$. It started with an increase in $2000$. Then the strength of the school in $2003$ as compared to that in $2000$ was

$37 \frac{1}{2} \%$ of $₹ 48$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module