One type of liquid contains 20 % water and th | vedclass

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(B) The total volume of the mixture is $10 + 4 = 14$ parts.Amount of water from the first liquid $= 10 	imes \frac{20}{100} = 2$ parts.Amount of wate

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$24 \frac{2}{7} \%$

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(B) The total volume of the mixture is $10 + 4 = 14$ parts.Amount of water from the first liquid $= 10 	imes \frac{20}{100} = 2$ parts.Amount of water from the second liquid $= 4 	imes \frac{35}{100} = 1.4$ parts.Total amount of water in the mixture $= 2 + 1.4 = 3.4$ parts.Percentage of water in the mixture $= \left( \frac{	ext{Total water}}{	ext{Total volume}} ight) 	imes 100 = \left( \frac{3.4}{14} ight) 	imes 100$.$= \frac{340}{14} = \frac{170}{7} = 24 \frac{2}{7} \%$.

One type of liquid contains $20 \%$ water and the second type of liquid contains $35 \%$ water. $A$ glass is filled with $10$ parts of the first liquid and $4$ parts of the second liquid. What is the percentage of water in the new mixture in the glass?

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