Optically active 2-octanol rapidly loses its | vedclass

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Question

(A) The optical activity of $2-$octanol is due to the presence of a chiral carbon atom at the $C-2$ position.When treated with dilute acid,$2-$octanol

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dilute acid

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(A) The optical activity of $2-$octanol is due to the presence of a chiral carbon atom at the $C-2$ position.When treated with dilute acid,$2-$octanol undergoes an acid-catalyzed dehydration reaction.This reaction leads to the formation of an alkene (octene),which is an achiral molecule.Since the chiral center is destroyed during the formation of the double bond,the molecule loses its optical activity.$CH_3-CH(OH)-(CH_2)_5-CH_3 \xrightarrow{dil. \, acid} CH_3-CH=CH-(CH_2)_4-CH_3 + H_2O$

Optically active $2-$octanol rapidly loses its optical activity when exposed to

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