Determine the order of bond length for the C- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In structure $x$ (cyclohexylamine),the $C-N$ bond is a pure single bond because there is no resonance. In structure $z$ (aniline),the lone pair on

Vedclass · Accepted Answer

$x > z > y$

Vedclass · Answer

(A) In structure $x$ (cyclohexylamine),the $C-N$ bond is a pure single bond because there is no resonance. In structure $z$ (aniline),the lone pair on the nitrogen atom is in conjugation with the benzene ring,which imparts partial double bond character to the $C-N$ bond,thereby shortening it. In structure $y$ ($p$-nitroaniline),the $-NO_2$ group is a strong electron-withdrawing group that increases the extent of resonance between the $-NH_2$ group and the benzene ring. This results in a greater partial double bond character in the $C-N$ bond compared to aniline $(z)$. Therefore,the bond length order is $x$ (single bond) $>$ $z$ (partial double bond) $>$ $y$ (greater partial double bond character). The correct order is $x > z > y$.

Determine the order of bond length for the $C-N$ bonds labeled as $x$,$y$,and $z$ in the given structures.

Similar Questions

Which of the following compounds does not exhibit the resonance effect?

Which of the following is the most unstable resonating structure of phenol?

$A$ molecule may be represented by three structures having energies $E_1$,$E_2$ and $E_3$,respectively. The energies of these structures follow the order $E_3 < E_2 < E_1$. If the experimental bond energy of the molecule is $E_0$,the resonance energy is

$CH_2 = O \leftrightarrow \overset{\oplus}{C}H_2 - \overset{\ominus}{O} \leftrightarrow \overset{\ominus}{C}H_2 - \overset{\oplus}{O}$
Which of these structures is practically not a valid canonical structure for formaldehyde?

The number of resonance structures for $N$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module