Out of 450 students of a school,325 play foot | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Total number of students in the school $= 450$.Number of students who play neither football nor cricket $= 50$.Therefore,the number of students wh

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(C) Total number of students in the school $= 450$.Number of students who play neither football nor cricket $= 50$.Therefore,the number of students who play at least one game (either football or cricket) is $n(F \cup C) = 450 - 50 = 400$.Given that the number of students who play football is $n(F) = 325$ and the number of students who play cricket is $n(C) = 175$.Using the set theory formula: $n(F \cup C) = n(F) + n(C) - n(F \cap C)$.Substituting the values: $400 = 325 + 175 - n(F \cap C)$.$400 = 500 - n(F \cap C)$.$n(F \cap C) = 500 - 400 = 100$.Thus,$100$ students play both football and cricket.

Out of $450$ students of a school,$325$ play football,$175$ play cricket and $50$ neither play football nor cricket. How many students play both football and cricket?

Similar Questions

The price of sugar has fallen by $10 \%$. How many quintals can be bought for the same money which was sufficient to buy $18$ quintals at the higher price?

The population of a town is $32000$. It increases $15\%$ annually. What will it be in $2$ years?

$860\%$ of $50 + 50\%$ of $860 = ?$

If $P \%$ of $P$ is $36,$ then $P$ is equal to

$x$ is $30 \%$ more than $y$ and $25 \%$ less than $z$. If the value of $y$ is $₹ 300$,then what is the value (in $₹$) of $z$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module