Out of BeF_{2}, MgF_{2}, CaF_{2}, SrF_{2},whi | vedclass

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Question

(A) The solubility of alkaline earth metal fluorides is determined by the balance between lattice energy and hydration energy.For small cations like $

Vedclass · Accepted Answer

$BeF_{2}$

Vedclass · Answer

(A) The solubility of alkaline earth metal fluorides is determined by the balance between lattice energy and hydration energy.For small cations like $Be^{2+}$,the hydration energy is significantly higher than the lattice energy,making $BeF_{2}$ highly soluble in water.As the size of the cation increases from $Be^{2+}$ to $Sr^{2+}$,the hydration energy decreases more rapidly than the lattice energy,leading to a decrease in solubility.Therefore,$BeF_{2}$ has the maximum solubility among the given compounds.

Out of $BeF_{2}, MgF_{2}, CaF_{2}, SrF_{2}$,which has maximum solubility?

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