Out of the following bulbs rated 40 W, 220 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The resistance of a bulb is given by the formula $R = \frac{V^2}{P}$.Since all bulbs have the same voltage rating $(V = 220 \ V)$,the resistance i

Vedclass · Accepted Answer

$40 \ W$ bulb

Vedclass · Answer

(A) The resistance of a bulb is given by the formula $R = \frac{V^2}{P}$.Since all bulbs have the same voltage rating $(V = 220 \ V)$,the resistance is inversely proportional to the power $(R \propto \frac{1}{P})$.Therefore,the $40 \ W$ bulb has the highest resistance.When bulbs are connected in series,the same current $(I)$ flows through each bulb.The power dissipated (brightness) in each bulb is given by $P_{actual} = I^2 R$.Since $I$ is constant for all bulbs in series,the brightness is directly proportional to the resistance $(P_{actual} \propto R)$.Because the $40 \ W$ bulb has the highest resistance,it will dissipate the most power and glow the brightest.

Out of the following bulbs rated $40 \ W, 220 \ V$,$60 \ W, 220 \ V$,and $100 \ W, 220 \ V$,which one will glow the brightest when connected in series to a supply of $220 \ V$?

Similar Questions

In the following circuits (Figure),heat produced in the resistor or combination of resistors connected to a $12\, V$ battery will be

What are the essential requirements of a heater filament?

Is electrostatic potential a scalar quantity or a vector quantity?

What is the other name of the commercial unit of electrical energy?

Which of the following materials has the highest number of free electrons?

Vedclass Test Series

Exam Paper Generator

Online Exam Module