Out of the two compounds A (p-nitrophenol) an | vedclass

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(A) $o$-Nitrophenol $(B)$ exhibits intramolecular hydrogen bonding,which restricts intermolecular hydrogen bonding between its molecules. This makes i

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higher than that of $A$

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(A) $o$-Nitrophenol $(B)$ exhibits intramolecular hydrogen bonding,which restricts intermolecular hydrogen bonding between its molecules. This makes it more volatile.$p$-Nitrophenol $(A)$ exhibits intermolecular hydrogen bonding,which leads to the association of molecules,resulting in a higher boiling point and lower volatility.Since vapour pressure is inversely related to boiling point,$o$-nitrophenol $(B)$ will have a higher vapour pressure than $p$-nitrophenol $(A)$.

Out of the two compounds $A$ ($p$-nitrophenol) and $B$ ($o$-nitrophenol) shown below,the vapour pressure of $B$ at a particular temperature is expected to be:

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