Out of two copper spheres of the same size,x | vedclass

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(D) For a conducting sphere,the electric potential $V$ at the surface is given by $V = \frac{kQ}{R}$,where $k$ is Coulomb's constant,$Q$ is the charge

Vedclass · Accepted Answer

Charge on both the spheres is equal.

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(D) For a conducting sphere,the electric potential $V$ at the surface is given by $V = \frac{kQ}{R}$,where $k$ is Coulomb's constant,$Q$ is the charge on the sphere,and $R$ is the radius of the sphere.Since both spheres are made of copper (a conductor) and have the same size,they have the same radius $R$.Given that both spheres are charged to the same potential $V$,we have $V_x = V_y = V$.Using the formula $V = \frac{kQ}{R}$,we get $V = \frac{kQ_x}{R}$ and $V = \frac{kQ_y}{R}$.Equating the two,we find $\frac{kQ_x}{R} = \frac{kQ_y}{R}$,which implies $Q_x = Q_y$.Therefore,the charge on both spheres is equal,regardless of whether the sphere is hollow or solid,because the charge on a conductor resides entirely on its outer surface.

Out of two copper spheres of the same size,$x$ is hollow while $y$ is solid. If they are charged at the same potential,what can be said about the charges on them?

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