Oxidation number of $Cl$ in $CaOCl_2$ (bleaching powder) is

  • A
    Zero,since it contains $Cl_2$
  • B
    $-1$,since it contains $Cl^{-}$
  • C
    $+1$,since it contains $ClO^{-}$
  • D
    $+1$ and $-1$ since it contains $ClO^{-}$ and $Cl^{-}$

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