The oxidation number of carbon in CH_3Cl is: | vedclass

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Question

(B) To find the oxidation number of carbon $(x)$ in $CH_3Cl$:Assign oxidation states to other atoms: Hydrogen $(H)$ is $+1$ and Chlorine $(Cl)$ is $-1

Vedclass · Accepted Answer

$-2$

Vedclass · Answer

(B) To find the oxidation number of carbon $(x)$ in $CH_3Cl$:Assign oxidation states to other atoms: Hydrogen $(H)$ is $+1$ and Chlorine $(Cl)$ is $-1$.The sum of oxidation numbers in a neutral molecule is $0$.$x + 3(+1) + (-1) = 0$$x + 3 - 1 = 0$$x + 2 = 0$$x = -2$Therefore,the oxidation number of carbon is $-2$.

The oxidation number of carbon in $CH_3Cl$ is:

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