(B) Let the oxidation number of $N$ in $NaNO_2$ be $x$.$Na$ has an oxidation number of $+1$ and $O$ has an oxidation number of $-2$.Sum of oxidation n

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(B) Let the oxidation number of $N$ in $NaNO_2$ be $x$.$Na$ has an oxidation number of $+1$ and $O$ has an oxidation number of $-2$.Sum of oxidation numbers in a neutral compound is $0$.$(+1) + x + 2 \times (-2) = 0$$1 + x - 4 = 0$$x - 3 = 0$$x = +3$