Oxygen consists of O^{16}, O^{17} and O^{18} | vedclass

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(B) $CO_2$ molecule consists of one carbon atom and two oxygen atoms. Let the isotopes of carbon be $C_1, C_2$ (total $2$) and isotopes of oxygen be $

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$12$

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(B) $CO_2$ molecule consists of one carbon atom and two oxygen atoms. Let the isotopes of carbon be $C_1, C_2$ (total $2$) and isotopes of oxygen be $O_1, O_2, O_3$ (total $3$). The structure of $CO_2$ is $O-C-O$. The number of ways to choose the carbon atom is $2$. The number of ways to choose the two oxygen atoms (where order does not matter as the two positions are equivalent) is given by the combination with repetition formula: $\frac{n(n+1)}{2}$,where $n=3$. Number of ways to choose oxygen atoms = $\frac{3(3+1)}{2} = \frac{12}{2} = 6$. Total number of $CO_2$ molecules = (Ways to choose $C$) $	imes$ (Ways to choose $O$ pair) = $2 	imes 6 = 12$.

Oxygen consists of $O^{16}, O^{17}$ and $O^{18}$ isotopes and carbon consists of isotopes of $C^{12}$ and $C^{13}$. Total number of $CO_2$ molecules possible are

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