Which of the following pairs of compounds is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ has $d^8$ configuration. $CN^-$ is a strong field ligand,causing pairing of electrons. It undergoes $dsp^2$ hybr

Vedclass · Accepted Answer

$[Ni(CN)_4]^{2-}, [Rh(CO)_2(PPh_3)_2]^+$

Vedclass · Answer

(C) $1$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ has $d^8$ configuration. $CN^-$ is a strong field ligand,causing pairing of electrons. It undergoes $dsp^2$ hybridization,resulting in a square planar geometry.$2$. $[Rh(CO)_2(PPh_3)_2]^+$: $Rh^+$ has $d^8$ configuration. Being a $4d$ series metal,it forms square planar complexes with strong field ligands like $CO$ and $PPh_3$. Thus,it is square planar.$3$. $[NiCl_4]^{2-}$ is tetrahedral $(sp^3)$.$4$. $[Ni(CO)_4]$ is tetrahedral $(sp^3)$.$5$. $[PtCl_4]^{2-}$ is square planar,but $[Ni(CN)_4]^{3-}$ is not a common stable species (usually $Ni(I)$ or $Ni(II)$ complexes are considered).Therefore,the pair $[Ni(CN)_4]^{2-}$ and $[Rh(CO)_2(PPh_3)_2]^+$ consists of two square planar complexes.

Which of the following pairs of compounds is planar?

Similar Questions

Which of the following statements is correct?

Which of the following statements is $NOT$ correct regarding the complex $[Co(NH_3)_6]^{3+}$?

Octahedral complexes of copper $(II)$ undergo structural distortion (Jahn-Teller). Which one of the given copper $(II)$ complexes will show the maximum structural distortion?
($en = \text{ethylenediamine}$; $H_2N-CH_2-CH_2-NH_2$)

Which of the following complexes exhibits square planar geometry?

The geometries of some complex ions are given below. Select the correct answer.
$(1) [Ag(NH_3)_2]^+ - \text{Linear}$
$(2) [MnCl_4]^{2-} - \text{Tetrahedral}$
$(3) [Cu(NH_3)_4]^{2+} - \text{Square planar}$
$(4) [Ni(CN)_4]^{2-} - \text{Square planar}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module