Phenol xrightarrow[Delta ]{Zn} A xrightarrow[ | vedclass

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(C) $1$. Phenol reacts with $Zn$ dust upon heating to form benzene $(A)$.$C_6H_5OH + Zn \xrightarrow{\Delta} C_6H_6 + ZnO$$2$. Benzene undergoes Fried

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Benzoic acid

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(C) $1$. Phenol reacts with $Zn$ dust upon heating to form benzene $(A)$.$C_6H_5OH + Zn \xrightarrow{\Delta} C_6H_6 + ZnO$$2$. Benzene undergoes Friedel-Crafts alkylation with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ to form toluene $(B)$.$C_6H_6 + CH_3Cl \xrightarrow{	ext{Anhydrous } AlCl_3} C_6H_5CH_3 + HCl$$3$. Toluene is oxidized by alkaline $KMnO_4$ upon heating to form benzoic acid $(C)$.$C_6H_5CH_3 \xrightarrow[\Delta]{KMnO_4/OH^-} C_6H_5COOH$Thus,the final product $C$ is benzoic acid.

Phenol $\xrightarrow[\Delta ]{Zn} A$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl} B$ $\xrightarrow[\Delta ]{KMnO_4/OH^{-}} C$
The product $C$ is

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Phenol $\xrightarrow[\Delta ]{Zn} A$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl} B$ $\xrightarrow[\Delta ]{KMnO_4/OH^{-}} C$The product $C$ is