Phenol in the presence of sodium hydroxide reacts with chloroform to form salicylaldehyde. This reaction is known as:

The major product of the following reaction sequence is:
$C_6H_5OH \xrightarrow[(ii) NaOH, (iii) H^+]{(i) CHCl_3, NaOH(aq)} ?$

The major product of the following reaction sequence is:
Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$

The compound which reacts with excess bromine to produce $2,4,6$-tribromophenol is

$C_6H_6 + CH_3-CH=CH_2$ $\xrightarrow{H_3PO_4} A$ $\xrightarrow{O_2, \text{heat}} B$ $\xrightarrow{\text{dil. } H_2SO_4} C + D$. $A, C$ and $D$ are:

Provide the alkylation and acylation reactions of anisole.