Phenylmethanol can be prepared by reducing benzaldehyde with:

In column - $I$ reaction name,in column - $II$ reactant and in column - $III$ product are given,match column - $I$ with column - $II$ and column - $III$ with the correct option.

Column - $I$ and $II$	Column - $III$
$(A).$ Rosenmund reaction - $(i).$ $H_2, Pd, BaSO_4$	$(p).$ Benzene to benzaldehyde
$(B).$ Stephen reaction - $(iii).$ $SnCl_2, HCl$	$(q).$ Benzoyl chloride to benzaldehyde
$(C).$ Etard reaction - $(iv).$ $CrO_2Cl_2, CS_2$	$(r).$ Toluene to chromium complex
$(D).$ Gatterman-Koch reaction - $(ii).$ $CO, HCl$ anhydrous $AlCl_3/CuCl$	$(s).$ $RCN \to RCHO$

Match the reactants in column $-I$ with the reaction conditions in column $-II$ to find the corresponding products in column $-III$.

Column $-I$ (Reactant)	Column $-II$ (Reaction Condition)	Column $-III$ (Product)
$A$. $CH_3CN + C_6H_5MgBr$	$i$. $Ether, H_3O^+$	$p$. Benzaldehyde
$B$. $Benzene + CH_3COCl$	$ii$. $Hg^{2+}, H_2SO_4, H_2O$	$q$. Acetophenone
$C$. $Toluene$	$iii$. $Anhydrous AlCl_3$	$r$. Propiophenone
$D$. $Phenyl ethyne$	$iv$. $x. Cl_2, hv$; $y. H_2O, 373 \ K$	$s$. Acetaldehyde

The major product obtained in the reaction of bromobenzene with $Mg$ in dry ether followed by the reaction with benzonitrile and hydrolysis is

In the reaction $C_6H_6 + CO + HCl \xrightarrow{A} C_6H_5CHO + HCl$,what is $A$?

The correct match between Item-$I$ (starting material) and Item-$II$ (reagent) for the preparation of benzaldehyde is :

Item-$I$	Item-$II$
$I$. Benzene	$P$. $HCl$ and $SnCl_2, H_3O^{+}$
$II$. Benzonitrile	$Q$. $H_2, Pd-BaSO_4, S$ and quinoline
$III$. Benzoyl Chloride	$R$. $CO, HCl$ and $AlCl_3$