Phosphorus on reaction with sulphuryl chlorid | vedclass

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Question

(C) The reaction of white phosphorus $(P_4)$ with sulphuryl chloride $(SO_2Cl_2)$ produces phosphorus pentachloride $(PCl_5)$ as the compound $X$.$P_4

Vedclass · Accepted Answer

$PCl_5, H_3PO_4$

Vedclass · Answer

(C) The reaction of white phosphorus $(P_4)$ with sulphuryl chloride $(SO_2Cl_2)$ produces phosphorus pentachloride $(PCl_5)$ as the compound $X$.$P_4 + 10SO_2Cl_2 \rightarrow 4PCl_5 + 10SO_2$When $PCl_5$ undergoes complete hydrolysis, it reacts with water to form phosphoric acid $(H_3PO_4)$ as the compound $Y$.$PCl_5 + 4H_2O \rightarrow H_3PO_4 + 5HCl$Therefore, $X$ is $PCl_5$ and $Y$ is $H_3PO_4$.

Phosphorus on reaction with sulphuryl chloride gives a compound $X$, which on complete hydrolysis gives $Y$. $X$ and $Y$ are respectively

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