Phosphorus reacts with SO_2Cl_2 to form PCl_5 | vedclass

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Question

(A) The reaction of phosphorus with sulfuryl chloride $(SO_2Cl_2)$ is: $P_4 + 10 SO_2Cl_2 \longrightarrow 4 PCl_5 + 10 SO_2$ $(X = SO_2)$.At $723 \ K$

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$H_2SO_4, HCl$

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(A) The reaction of phosphorus with sulfuryl chloride $(SO_2Cl_2)$ is: $P_4 + 10 SO_2Cl_2 \longrightarrow 4 PCl_5 + 10 SO_2$ $(X = SO_2)$.At $723 \ K$,the Deacon process for the manufacture of chlorine is: $4 HCl + O_2 \xrightarrow[CuCl_2]{723 \ K} 2 Cl_2 + 2 H_2O$ $(Y = Cl_2)$.$Cl_2$ $(Y)$ reacts with $SO_2$ $(X)$ in the presence of water to form hydrochloric acid $(A)$ and sulfuric acid $(B)$: $SO_2 + 2 H_2O + Cl_2 \longrightarrow 2 HCl + H_2SO_4$.

$A$. $F_2$	$I$. Red
$B$. $Cl_2$	$II$. Violet
$C$. $Br_2$	$III$. Yellow
$D$. $I_2$	$IV$. Greenish yellow

Phosphorus reacts with $SO_2Cl_2$ to form $PCl_5$ and $X$. At $723 \ K$,$HCl$ gas reacts with $O_2$ in the presence of $CuCl_2$ to form water and $Y$. $Y$ reacts with $X$ in water to form two acids $A$ and $B$. What are $A$ and $B$ respectively?

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