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Question

(B) The conductivity of an electrolytic solution depends on the number of ions produced upon dissociation.$1$. $K_2[PtCl_6] \rightarrow 2K^+ + [PtCl_6

Vedclass · Accepted Answer

$[Co(NH_3)_3(NO_2)_3]$

Vedclass · Answer

(B) The conductivity of an electrolytic solution depends on the number of ions produced upon dissociation.$1$. $K_2[PtCl_6] \rightarrow 2K^+ + [PtCl_6]^{2-}$ ($3$ ions)$2$. $[Co(NH_3)_3(NO_2)_3] \rightarrow$ No ions (non-ionizable as it is a neutral complex)$3$. $K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}$ ($5$ ions)$4$. $[Cu(NH_3)_4]SO_4 \rightarrow [Cu(NH_3)_4]^{2+} + SO_4^{2-}$ ($2$ ions)Since $[Co(NH_3)_3(NO_2)_3]$ does not produce any ions in solution,it is a poor electrolytic conductor.

Pick out from the following complex compounds,a poor electrolytic conductor in solution.

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