Pipes A and B can fill a tank in 5 hours and | vedclass

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(C) Pipe $A$ can fill $\frac{1}{5}$ part of the tank in $1$ hour.Pipe $B$ can fill $\frac{1}{6}$ part of the tank in $1$ hour.Pipe $C$ can empty $\fra

Vedclass · Accepted Answer

$3 \frac{9}{17} 	ext{ hours}$

Vedclass · Answer

(C) Pipe $A$ can fill $\frac{1}{5}$ part of the tank in $1$ hour.Pipe $B$ can fill $\frac{1}{6}$ part of the tank in $1$ hour.Pipe $C$ can empty $\frac{1}{12}$ part of the tank in $1$ hour.When all three pipes $A, B,$ and $C$ are opened together,the net part of the tank filled in $1$ hour is:$= \frac{1}{5} + \frac{1}{6} - \frac{1}{12}$Taking the least common multiple $(LCM)$ of $5, 6,$ and $12$,which is $60$:$= \frac{12 + 10 - 5}{60} = \frac{17}{60}$ part per hour.Therefore,the total time taken to fill the tank is the reciprocal of the work done in $1$ hour:$= \frac{1}{17/60} = \frac{60}{17} 	ext{ hours} = 3 \frac{9}{17} 	ext{ hours}$.

Pipes $A$ and $B$ can fill a tank in $5$ $hours$ and $6$ $hours$ respectively. Pipe $C$ can empty it in $12$ $hours.$ If all the three pipes are opened together,then the tank will be filled in

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