Platinum crystallizes in a face-centered cubi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a face-centered cubic $(FCC)$ unit cell,the atoms touch each other along the face diagonal. The length of the face diagonal is $d = a\sqrt{2}$.

Vedclass · Accepted Answer

$a \frac{\sqrt{2}}{2}$

Vedclass · Answer

(C) In a face-centered cubic $(FCC)$ unit cell,the atoms touch each other along the face diagonal. The length of the face diagonal is $d = a\sqrt{2}$. Since the face diagonal consists of two radii of the corner atoms and the diameter of the face-centered atom,we have $4r = a\sqrt{2}$,where $r$ is the radius of the atom. The distance between the nearest neighbour atoms is equal to $2r$. From $4r = a\sqrt{2}$,we get $2r = \frac{a\sqrt{2}}{2} = a \frac{\sqrt{2}}{2}$.

Platinum crystallizes in a face-centered cubic $(FCC)$ crystal with a unit cell edge length $a$. The distance between nearest neighbour atoms is

Similar Questions

Gold has a face-centred cubic $(fcc)$ lattice with an edge length of the unit cube of $407 \ pm$. Assuming the closest packing, the diameter of the gold atom is .............. $pm$.

How many atoms are there in a cube-based unit cell,having one atom on each corner and $2$ atoms on each body diagonal of the cube?

In a face-centered cubic arrangement of $A$ and $B$ atoms,$A$ atoms are at the corners of the unit cell and $B$ atoms are at the face centers. If one of the $B$ atoms is missing from one of the faces in the unit cell,the simplest formula of the compound is:

The tetrahedral voids formed by $ccp$ arrangement of $Cl^{-}$ ions in rock salt structure are

Explain the calculation of the number of atoms in a body-centered cubic $(bcc)$ unit cell.

Vedclass Test Series

Exam Paper Generator

Online Exam Module