Point B is 12 ,meters south of point A. Point | vedclass

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Question

(A) Let us represent the positions on a coordinate plane,starting with point $B$ at $(0, 0).$Point $A$ is $12 \,meters$ north of $B$,so $A = (0, 12).$

Vedclass · Accepted Answer

$12 \,meters$ west

Vedclass · Answer

(A) Let us represent the positions on a coordinate plane,starting with point $B$ at $(0, 0).$Point $A$ is $12 \,meters$ north of $B$,so $A = (0, 12).$Point $C$ is $24 \,meters$ east of $B$,so $C = (24, 0).$Point $D$ is $8 \,meters$ south of $C$,so $D = (24, -8).$Point $D$ is $12 \,meters$ east of $E$,which means $E$ is $12 \,meters$ west of $D$. So,$E = (24 - 12, -8) = (12, -8).$Point $F$ is $8 \,meters$ north of $E$,so $F = (12, -8 + 8) = (12, 0).$Now,we need to find the position of $F$ relative to $C$.$C = (24, 0)$ and $F = (12, 0).$The distance between $C$ and $F$ is $24 - 12 = 12 \,meters.$Since the $x$-coordinate of $F$ is less than the $x$-coordinate of $C$,$F$ is to the west of $C$.Therefore,point $F$ is $12 \,meters$ west of point $C$.

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