The potential difference across the terminals | vedclass

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Question

(A) The circuit consists of a battery with electromotive force $E = 10 \ V$ and internal resistance $r = 1 \ \Omega$,connected in series with an exter

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$8$

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(A) The circuit consists of a battery with electromotive force $E = 10 \ V$ and internal resistance $r = 1 \ \Omega$,connected in series with an external resistor $R = 4 \ \Omega$.The total resistance of the circuit is $R_{total} = R + r = 4 \ \Omega + 1 \ \Omega = 5 \ \Omega$.The current $I$ flowing through the circuit is given by Ohm's law: $I = \frac{E}{R_{total}} = \frac{10 \ V}{5 \ \Omega} = 2 \ A$.The potential difference $V$ across the terminals of the battery is given by the formula $V = E - Ir$.Substituting the values: $V = 10 \ V - (2 \ A 	imes 1 \ \Omega) = 10 \ V - 2 \ V = 8 \ V$.

The potential difference across the terminals of the battery shown in the figure is .................... $V$. ($E = 10 \ V$,$r = 1 \ \Omega$,external resistance $R = 4 \ \Omega$) (in $V$)

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