Power delivered by the $ac$ source of the circuit becomes maximum when

What is the value of inductance $L$ for which the current is a maximum in a series $LCR$ circuit with $C=10 \mu F$ and $\omega=1000 \ s^{-1}$?

$A$ resistor of resistance $R$, an inductor of inductive reactance $2R$, and a capacitor of capacitive reactance $X_C$ are connected in series to an $A.C.$ source. If the series $LCR$ circuit is in resonance, then the power factor of the circuit and the value $X_C$ are respectively:

The total impedance of a series $L-C-R$ circuit varies with the angular frequency of the $AC$ source connected to it,as shown in the graph. The quality factor $Q$ of the series $L-C-R$ circuit is:

In a series resonant $LCR$ circuit,the voltage across $R$ is $100 \ V$ and $R = 1 \ k\Omega$ with $C = 2 \ \mu F$. The resonant frequency $\omega$ is $200 \ rad/s$. At resonance,the voltage across $L$ is:

In an $LRC$ series circuit at resonance,the current in the circuit is $10\sqrt{2} \ A$. If the frequency of the source is changed such that the current now lags by $45^o$ behind the applied voltage,which of the following is correct?