Class 11ChemistryClassification of Elements and Periodicity in PropertiesValency and oxidation state
MediumPredict the formula of the stable binary compounds that would be formed by the combination of the following pairs of elements:
$(a)$ Lithium and oxygen
$(b)$ Magnesium and nitrogen
$(c)$ Aluminium and iodine
$(d)$ Silicon and oxygen
$(e)$ Phosphorus and fluorine
$(f)$ Element $71$ and fluorine
$(a)$ Lithium and oxygen
$(b)$ Magnesium and nitrogen
$(c)$ Aluminium and iodine
$(d)$ Silicon and oxygen
$(e)$ Phosphorus and fluorine
$(f)$ Element $71$ and fluorine
(N/A) Lithium $(Li)$ has a valency of $1$ and oxygen $(O)$ has a valency of $2$. The formula is $Li_2O$.
$(b)$ Magnesium $(Mg)$ has a valency of $2$ and nitrogen $(N)$ has a valency of $3$. The formula is $Mg_3N_2$.
$(c)$ Aluminium $(Al)$ has a valency of $3$ and iodine $(I)$ has a valency of $1$. The formula is $AlI_3$.
$(d)$ Silicon $(Si)$ has a valency of $4$ and oxygen $(O)$ has a valency of $2$. The formula is $SiO_2$.
$(e)$ Phosphorus $(P)$ can show valencies of $3$ or $5$ and fluorine $(F)$ has a valency of $1$. The formulas are $PF_3$ or $PF_5$.
$(f)$ The element with atomic number $71$ is Lutetium $(Lu)$,which has a valency of $3$. Fluorine $(F)$ has a valency of $1$. The formula is $LuF_3$.
$(b)$ Magnesium $(Mg)$ has a valency of $2$ and nitrogen $(N)$ has a valency of $3$. The formula is $Mg_3N_2$.
$(c)$ Aluminium $(Al)$ has a valency of $3$ and iodine $(I)$ has a valency of $1$. The formula is $AlI_3$.
$(d)$ Silicon $(Si)$ has a valency of $4$ and oxygen $(O)$ has a valency of $2$. The formula is $SiO_2$.
$(e)$ Phosphorus $(P)$ can show valencies of $3$ or $5$ and fluorine $(F)$ has a valency of $1$. The formulas are $PF_3$ or $PF_5$.
$(f)$ The element with atomic number $71$ is Lutetium $(Lu)$,which has a valency of $3$. Fluorine $(F)$ has a valency of $1$. The formula is $LuF_3$.
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| Element | Information |
|---|---|
| $P$ | Period number: $2$,Group number: $15$ |
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