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(A) $NaBH_4$ is a selective reducing agent that reduces aldehydes and ketones to alcohols but does not reduce esters or carboxylic acids. In the given

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(A) $NaBH_4$ is a selective reducing agent that reduces aldehydes and ketones to alcohols but does not reduce esters or carboxylic acids. In the given compound,there is a ketone group and an ester group. $NaBH_4$ will selectively reduce the ketone group to a secondary alcohol while leaving the ester group intact. Therefore,the product is a compound containing both a primary alcohol (from the original structure) and a secondary alcohol (formed from the ketone),with the ester group remaining unchanged. This corresponds to option $(A)$.

Predict the product when the given compound $(A)$ reacts with $NaBH_4$.

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