Pressure remaining the same,the volume of a g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Charles's Law,the relationship between volume and temperature at constant pressure is given by: $V_t = V_0(1 + \alpha_v t)$.Here,$V_t

Vedclass · Accepted Answer

$0\,^{\circ}C$

Vedclass · Answer

(A) According to Charles's Law,the relationship between volume and temperature at constant pressure is given by: $V_t = V_0(1 + \alpha_v t)$.Here,$V_t$ is the volume at $t\,^{\circ}C$,$V_0$ is the volume at $0\,^{\circ}C$,and $\alpha_v$ is the coefficient of volume expansion,which is equal to $\frac{1}{273.15}\,^{\circ}C^{-1}$.For every $1\,^{\circ}C$ rise in temperature,the change in volume $\Delta V$ is given by $\Delta V = V_0 	imes \alpha_v 	imes 1 = \frac{V_0}{273.15}$.Thus,the volume increases by a definite fraction $\frac{1}{273.15}$ of its volume at $0\,^{\circ}C$.

Pressure remaining the same,the volume of a given mass of an ideal gas increases for every degree centigrade rise in temperature by a definite fraction of its volume at:

Similar Questions

The density of $CO_2$ at $100\,^oC$ temperature and $400\,mm\,Hg$ pressure is .......... $g/L$.

At $273 \ K$ temperature and $76 \ cm \ of \ Hg$ pressure,the volume of $1.786 \ g$ of a gas is $1 \ L$. The gas is likely to be .........

The mass of a gas in a container at $1 \, \text{atm}$ pressure and $200 \, K$ temperature is $3.2 \, g$. What will be the mass of the same gas in the same container at $500 \, K$ temperature and $10 \, \text{atm}$ pressure?

$A$ gas occupies a volume of $0.35 \ dm^3$ at $290 \ K$ and $2 \ atm$ pressure. Calculate the volume of the gas at $STP$. (in $dm^3$)

The temperature of $4.0 \ mol$ of a gas occupying $5 \ dm^3$ at $3.32 \ bar$ is $(R = 0.083 \ bar \ dm^3 \ K^{-1} \ mol^{-1})$. (in $K$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module