The product (B) of the reaction is:CH(CO_2H)= | vedclass

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(C) The reaction sequence is as follows:$1$. Reaction with $2 \ mole$ of $NaOH$ converts the dicarboxylic acid into its sodium salt:$CH(CO_2H)=CH(CO_2

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$HC \equiv CH$

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(C) The reaction sequence is as follows:$1$. Reaction with $2 \ mole$ of $NaOH$ converts the dicarboxylic acid into its sodium salt:$CH(CO_2H)=CH(CO_2H) + 2NaOH ightarrow CH(CO_2Na)=CH(CO_2Na) + 2H_2O$Here,$(A)$ is sodium maleate (or fumarate).$2$. Kolbe's electrolytic synthesis involves the electrolysis of the aqueous solution of the sodium salt of a dicarboxylic acid.$CH(CO_2Na)=CH(CO_2Na) \xrightarrow{	ext{electrolysis}} HC \equiv CH + 2CO_2 + 2NaOH + H_2$Thus,the product $(B)$ is ethyne $(HC \equiv CH)$.

The product $(B)$ of the reaction is:
$CH(CO_2H)=CH(CO_2H)$ $\xrightarrow[2 \ mole]{NaOH} (A)$ $\xrightarrow{\text{electrolysis}} (B)$

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The product $(B)$ of the reaction is:$CH(CO_2H)=CH(CO_2H)$ $\xrightarrow[2 \ mole]{NaOH} (A)$ $\xrightarrow{\text{electrolysis}} (B)$