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(B) The reaction shown is an alkoxymercuration-demercuration of cyclohexene using mercury$(II)$ trifluoroacetate,$(CF_3CO_2)_2Hg$,and ethanol,$CH_3CH_

Vedclass · Accepted Answer

Ethoxycyclohexane

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(B) The reaction shown is an alkoxymercuration-demercuration of cyclohexene using mercury$(II)$ trifluoroacetate,$(CF_3CO_2)_2Hg$,and ethanol,$CH_3CH_2OH$,followed by reduction with $NaBH_4$ in the presence of base $(HO^-)$.This reaction follows Markovnikov's rule,where the alkoxy group $(-OCH_2CH_3)$ adds to the more substituted carbon of the double bond. Since cyclohexene is symmetric,the product formed is ethoxycyclohexane.

The product $(P)$ is:

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