Product (C) of the above reaction is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The reaction starts with benzene,which undergoes Birch reduction with $Na$ in liquid $NH_3$ to form $1,4-$cyclohexadiene $(A)$.$2$. Ozonolysi

Vedclass · Accepted Answer

$1,4-$pentadiene

Vedclass · Answer

(B) $1$. The reaction starts with benzene,which undergoes Birch reduction with $Na$ in liquid $NH_3$ to form $1,4-$cyclohexadiene $(A)$.$2$. Ozonolysis of $1,4-$cyclohexadiene followed by reductive workup with $Zn$ yields malonaldehyde $(OHC-CH_2-CHO)$ $(B)$.$3$. The reaction of malonaldehyde with $2$ moles of Wittig reagent $(Ph_3P=CH_2)$ converts both aldehyde groups into terminal alkene groups.$4$. The final product $(C)$ is $1,4-$pentadiene $(CH_2=CH-CH_2-CH=CH_2)$.

Product $(C)$ of the above reaction is

Similar Questions

What are $B$ and $C$ respectively in the following set of reactions?
$C \xleftarrow[\Delta]{Zn} 1,2-\text{dibromopropane}$ $\xrightarrow[\text {(ii) } NaNH_2]{\text {(i) alc. } KOH} A$ $\xrightarrow[\text { Catalyst }]{\text { Lindlar }} B$

Compound $(A)$ is

The formation of an innumerable number of carbon compounds is due to its:

The major product of the reaction is:

What are $X$ and $Y$ respectively in the following sets of reactions?
$I. \ CH_3CH_2CH_2OH \xrightarrow{PBr_3} X$
$II. \ CH_3CH=CH_2 \xrightarrow{HBr, (C_6H_5COO)_2} Y \text{ (major)}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module