Product (B) of the above reaction is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction starts with the protonation of the hydroxyl group of tetrahydrofurfuryl alcohol,followed by the loss of water to form a primary carbo

Vedclass · Accepted Answer

Tetrahydropyran$-2-$yl ether derivative

Vedclass · Answer

(A) The reaction starts with the protonation of the hydroxyl group of tetrahydrofurfuryl alcohol,followed by the loss of water to form a primary carbocation. This carbocation undergoes ring expansion to form a more stable six-membered oxocarbenium ion. Loss of a proton from this ion yields $3,4-$dihydro-2H-pyran as intermediate $(A)$. Subsequent acid-catalyzed addition of the alcohol $ROH$ to the double bond of $3,4-$dihydro-2H-pyran follows Markovnikov's rule,where the alkoxy group attaches to the carbon adjacent to the oxygen atom,resulting in the formation of a tetrahydropyran$-2-$yl ether derivative as the major product $(B)$.

Product $(B)$ of the above reaction is

Similar Questions

The strongest acid among the following is:

Which of the following is the most suitable reagent for the conversion of $RCH_2OH$ to $RCHO$?

The main product of the following reaction is:
$C_6H_5-CH_2-CH(OH)-CH(CH_3)_2 \xrightarrow{conc. H_2SO_4} ?$

The following reaction is known as:
$C_2H_5OH + SOCl_2 \xrightarrow{\text{Pyridine}} C_2H_5Cl + SO_2 + HCl$

In order to make alcohol undrinkable,pyridine and methanol are added to it. The resulting alcohol is called:

Vedclass Test Series

Exam Paper Generator

Online Exam Module