The product (A) of the above reaction is: | vedclass

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(D) The given reactant is $CH_3O-CH(CO_2H)-CH_2-CH_2-CH=CH-CH_2-CH_3$. Ozonolysis ($O_3$ followed by $(CH_3)_2S$) cleaves the $C=C$ double bond to for

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$CH_3O-CH(CO_2H)-CH_2-CH_2-CH_2-CHO$

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(D) The given reactant is $CH_3O-CH(CO_2H)-CH_2-CH_2-CH=CH-CH_2-CH_3$. Ozonolysis ($O_3$ followed by $(CH_3)_2S$) cleaves the $C=C$ double bond to form two carbonyl compounds. The cleavage results in: $CH_3O-CH(CO_2H)-CH_2-CH_2-CHO \ (A)$ and $CH_3-CH_2-CHO \ (B)$. Compound $(A)$ is optically active due to the chiral center at the carbon atom attached to the $-OCH_3$ and $-CO_2H$ groups. Therefore,the correct option is $(D)$.

The product $(A)$ of the above reaction is:

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