The product $(K)$ of the following reaction is:

  • A
    Option A
  • B
    Option B
  • C
    Option C
  • D
    Option D

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Compound $(X)$ [styrene] is subjected to the following sequence of reactions: $(i)$ $Br_2/CHCl_3$, $(ii)$ $NaNH_2$ (excess), $(iii)$ $CH_3I$, $(iv)$ $H_2, Na/NH_3(l)$, giving Major Product $(Y)$. The molar mass of the major product $(Y)$ formed is . . . . . . $\text{g mol}^{-1}$. (Given molar mass in $\text{g mol}^{-1}$: $C:12, H:1$)

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$CH_3C \equiv C^-Na^+ + (CH_3)_2CH-Cl \to$ What will be the product of this reaction?

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Predict the product $C$ obtained in the following reaction of $1-$butyne: $CH_3-CH_2-C \equiv CH + HCl$ $\rightarrow B$ $\xrightarrow{HI} C$

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