The product (N) is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Cyclohexanecarboxylic acid reacts with $LiH$ in dimethoxyethane to form the lithium salt of the acid,$(L)$,which is cyclohexanecarboxylate li

Vedclass · Accepted Answer

Cyclohexanecarboxylic acid

Vedclass · Answer

(C) $1$. Cyclohexanecarboxylic acid reacts with $LiH$ in dimethoxyethane to form the lithium salt of the acid,$(L)$,which is cyclohexanecarboxylate lithium,$C_6H_{11}COOLi$.$2$. The lithium salt $(L)$ then reacts with methyllithium $(CH_3Li)$. However,the carboxylate salt is generally unreactive towards nucleophilic attack by organolithium reagents under these conditions,or it forms a stable intermediate $(M)$ which is the methyl ester,$C_6H_{11}COOCH_3$,upon workup or specific reaction conditions.$3$. The final step is the hydrolysis of $(M)$ with $H_3O^+$. The hydrolysis of the ester $C_6H_{11}COOCH_3$ yields the original carboxylic acid,cyclohexanecarboxylic acid $(N)$,and methanol $(CH_3OH)$.$4$. Therefore,the product $(N)$ is cyclohexanecarboxylic acid.

The product $(N)$ is

Similar Questions

Which of the following reagents is used to obtain acetic anhydride from acetyl chloride?

Identify the structure of $Z$ in the following reaction sequence:
$Phthalic \ acid + NH_3 \rightleftharpoons X$ $\xrightarrow{\Delta} Y$ $\xrightarrow{\text{heating}} Z$

The refluxing of $(CH_3)_2NCOCH_3$ with acid gives

Identify the reagent used in the following reaction: $\text{Benzoic acid} \xrightarrow[\Delta]{\text{Reagent}} \text{Benzoyl chloride} + \text{Phosphorus oxychloride} + \text{Hydrogen chloride}$.

Correct order of $pK_{a}$ of given compounds is $:-$
$(P) \ CH_{3}COOH$
$(Q) \ FCH_{2}COOH$
$(R) \ ClCH_{2}COOH$
$(S) \ C_{2}H_{5}COOH$

Vedclass Test Series

Exam Paper Generator

Online Exam Module