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(C) The given reaction involves the Wolff-Kishner reduction of a ketone group $(C=O)$ to a methylene group $(-CH_2-)$ using $N_2H_4$ and $HO^-, \Delta

Vedclass · Accepted Answer

$1-$ethyl$-4-$($2$-bromoethyl)benzene

Vedclass · Answer

(C) The given reaction involves the Wolff-Kishner reduction of a ketone group $(C=O)$ to a methylene group $(-CH_2-)$ using $N_2H_4$ and $HO^-, \Delta$. $1$. The Wolff-Kishner reduction specifically targets the carbonyl group,converting the acetyl group $(-COCH_3)$ into an ethyl group $(-CH_2CH_3)$. $2$. The alkyl halide group $(-CH_2CH_2Br)$ remains unaffected by the Wolff-Kishner reduction conditions. $3$. Therefore,the product $(A)$ is $1-ethyl-4-(2-bromoethyl)benzene$.

The product $(A)$ is:

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