The product (B) in the given reaction is: | vedclass

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(C) $1$. The reaction of cyclohexylideneacetic acid with excess $CH_3Li$ followed by $HCl/H_2O$ converts the carboxylic acid group into a methyl keton

Vedclass · Accepted Answer

Sodium cyclohex$-1-$ene$-1-$carboxylate

Vedclass · Answer

(C) $1$. The reaction of cyclohexylideneacetic acid with excess $CH_3Li$ followed by $HCl/H_2O$ converts the carboxylic acid group into a methyl ketone,forming cyclohexylideneacetone $(A)$.$2$. The compound $(A)$ contains a methyl ketone group $(CH_3-CO-)$,which undergoes the haloform reaction with $I_2/NaOH$.$3$. The haloform reaction cleaves the methyl ketone to form a carboxylate salt and iodoform $(CHI_3)$.$4$. The product $(B)$ is sodium cyclohex$-1-$ene$-1-$carboxylate.

The product $(B)$ in the given reaction is:

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