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(A) In the Beckmann rearrangement,the group anti to the $-OH$ group on the nitrogen atom migrates to the nitrogen.In the first reaction,the $-CH_3$ gr

Vedclass · Accepted Answer

$Ph-C(=O)-NH-CH_3, CH_3-C(=O)-NH-Ph$

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(A) In the Beckmann rearrangement,the group anti to the $-OH$ group on the nitrogen atom migrates to the nitrogen.In the first reaction,the $-CH_3$ group is anti to the $-OH$ group. Therefore,the $-CH_3$ group migrates to the nitrogen,resulting in the product $Ph-C(=O)-NH-CH_3$.In the second reaction,the $-Ph$ group is anti to the $-OH$ group. Therefore,the $-Ph$ group migrates to the nitrogen,resulting in the product $CH_3-C(=O)-NH-Ph$.Thus,the products $(A)$ and $(B)$ are $Ph-C(=O)-NH-CH_3$ and $CH_3-C(=O)-NH-Ph$ respectively.

The products $(A)$ and $(B)$ respectively in the above Beckmann rearrangement reactions are:

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