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(D) The reaction sequence is as follows:$1$. The starting material is $p$-nitrobenzonitrile $(O_2N-C_6H_4-CN)$.$2$. Treatment with $1 \ mole$ of $HO^-

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(D) The reaction sequence is as follows:$1$. The starting material is $p$-nitrobenzonitrile $(O_2N-C_6H_4-CN)$.$2$. Treatment with $1 \ mole$ of $HO^-$ (alkaline hydrolysis) converts the nitrile group $(-CN)$ into an amide group $(-CONH_2)$.$3$. The resulting intermediate is $p$-nitrobenzamide $(O_2N-C_6H_4-CONH_2)$.$4$. Subsequent treatment with $HO^-$ and $Br_2$ constitutes the Hofmann bromamide degradation reaction.$5$. This reaction converts the amide group $(-CONH_2)$ into a primary amine group $(-NH_2)$,resulting in $p$-nitroaniline $(O_2N-C_6H_4-NH_2)$.$6$. Thus,the final product $(A)$ is $p$-nitroaniline.

Product $(A)$ is

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