The product $(A)$ of the reaction is:

If $B$ is the major product,then identify $B$.

Match List-$I$ with List-$II$:

List-$I$ Conversion	List-$II$ Reagents,Conditions used
$A$. Chlorobenzene $\rightarrow$ Phenol	$I$. Warm,$H_2O$
$B$. $1$-Chloro-$4$-nitrobenzene $\rightarrow$ $4$-Nitrophenol	$II$. $(a)$ $NaOH, 368 \ K$; $(b)$ $H_3O^+$
$C$. $1$-Chloro-$2,4$-dinitrobenzene $\rightarrow$ $2,4$-Dinitrophenol	$III$. $(a)$ $NaOH, 443 \ K$; $(b)$ $H_3O^+$
$D$. $1$-Chloro-$2,4,6$-trinitrobenzene $\rightarrow$ $2,4,6$-Trinitrophenol	$IV$. $(a)$ $NaOH, 623 \ K, 300 \ atm$; $(b)$ $H_3O^+$

Choose the correct answer from the options given below:

The reaction in which $2$ molecules of chlorobenzene react with metallic sodium in the presence of dry ether to form diphenyl is an example of:

The only $o, p-$ directing group which is deactivating in nature is

$CH \equiv CH$ $\xrightarrow{\text{Red Hot Fe tube}} A$ $\xrightarrow[\text{Dark}]{Cl_2 / FeCl_3} B$ $\xrightarrow[\text{Anhy. } AlCl_3]{CH_3 - Cl} C$ (Major)
Product '$C$' is