The product (B) in the given reaction is: | vedclass

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(C) $1$. The reaction of aniline with $Br_2/H_2O$ leads to electrophilic aromatic substitution,resulting in the formation of $2,4,6$-tribromoaniline a

Vedclass · Accepted Answer

$1,3,5-$tribromobenzene

Vedclass · Answer

(C) $1$. The reaction of aniline with $Br_2/H_2O$ leads to electrophilic aromatic substitution,resulting in the formation of $2,4,6$-tribromoaniline as product $(A)$.$2$. The treatment of $2,4,6$-tribromoaniline with $(i) NaNO_2/HCl$ at low temperature $(0-5 \ ^\circ C)$ forms the corresponding diazonium salt,$2,4,6$-tribromobenzenediazonium chloride.$3$. Subsequent treatment with $H_3PO_2$ (hypophosphorous acid) and water reduces the diazonium group to a hydrogen atom,resulting in the formation of $1,3,5$-tribromobenzene as product $(B)$.

The product $(B)$ in the given reaction is:

Similar Questions

Identify the product $Y$ in the following reaction sequence:
Phthalimide $\xrightarrow[(2) \text{Cyclohexyl chloride}, (3) H_2O/\Delta]{(1) KOH} X$ $\xrightarrow{CHCl_3, KOH, \Delta} Y$

The correct sequential order of the reagents for the given reaction is:

In the reaction sequence,
$X$ and $Y$ are,respectively

$A$. Phenyl methanamine
$B$. $N,N$-Dimethylaniline
$C$. $N$-Methylaniline
$D$. Benzenamine
Choose the correct order of basic nature of the above amines.

The preferred sites of protonation in the following compounds are:
$(i)$ $CH_3CONHCH_3$
(ii) $2$-aminopyridine

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