The product (4) in the given reaction sequenc | vedclass

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(B) $1$. The starting material is $4$-hydroxybenzoic acid. Treatment with $HNO_3$ (nitration) introduces a nitro group at the ortho position to the $-

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(B) $1$. The starting material is $4$-hydroxybenzoic acid. Treatment with $HNO_3$ (nitration) introduces a nitro group at the ortho position to the $-OH$ group,yielding $4$-hydroxy-$3$-nitrobenzoic acid.$2$. Reaction with a base followed by $n-PrCl$ (propyl chloride) performs an $S_N2$ alkylation of the phenolic $-OH$ group to form $4$-propoxy-$3$-nitrobenzoic acid.$3$. Treatment with $SOCl_2$ converts the carboxylic acid group into an acid chloride,forming $4$-propoxy-$3$-nitrobenzoyl chloride.$4$. Reaction with $Et_2NH$ (diethylamine) converts the acid chloride into an amide,yielding $N,N$-diethyl-$4$-propoxy-$3$-nitrobenzamide.$5$. Finally,catalytic hydrogenation using $H_2/Pd-C$ reduces the nitro group $(-NO_2)$ to an amino group $(-NH_2)$,resulting in the final product: $3$-amino-$4$-propoxy-$N,N$-diethylbenzamide.

The product $(4)$ in the given reaction sequence is:

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