The product (A) of the following reaction is: | vedclass

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(C) The reaction is an electrophilic aromatic substitution (nitration) of $6$-methoxytetralin using $HNO_3/H_2SO_4$.The $-OCH_3$ group is a strong act

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(C) The reaction is an electrophilic aromatic substitution (nitration) of $6$-methoxytetralin using $HNO_3/H_2SO_4$.The $-OCH_3$ group is a strong activating group and is ortho/para directing.In $6$-methoxytetralin,the positions ortho to the $-OCH_3$ group are the most reactive towards electrophilic substitution.Therefore,the nitro group $(-NO_2^+)$ will attack the position ortho to the $-OCH_3$ group,leading to the formation of $5$-nitro-$6$-methoxytetralin.Comparing this with the given options,option $(C)$ represents the correct product.

The product $(A)$ of the following reaction is:

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