The reaction is given as:Naphthalene + Oxalyl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The reaction of naphthalene with oxalyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts acylation reaction.$2$. This reaction leads

Vedclass · Accepted Answer

Acenaphthene

Vedclass · Answer

(C) $1$. The reaction of naphthalene with oxalyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts acylation reaction.$2$. This reaction leads to the formation of acenaphthenequinone,which is the intermediate $[X]$.$3$. The subsequent reduction of the carbonyl groups in $[X]$ using $Na-Hg$ and $HCl$ (Clemmensen reduction) converts the two ketone groups into methylene groups $(-CH_2-)$.$4$. This reduction process yields acenaphthene as the final product $[Y]$.

The reaction is given as:
Naphthalene + Oxalyl chloride $\xrightarrow{AlCl_3} [X]$ $\xrightarrow{Na-Hg, HCl \text{ (excess)}} [Y]$
Product $Y$ is:

Similar Questions

The reaction of benzene with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ gives :

Find the decreasing order of reactivity towards electrophilic substitution reaction for the following compounds:
$I$: Toluene $(C_6H_5CH_3)$
$II$: Benzene $(C_6H_6)$
$III$: Anisole $(C_6H_5OCH_3)$
$IV$: Trifluoromethylbenzene $(C_6H_5CF_3)$

In the presence of $AlCl_3$,benzene and $n$-propyl bromide react in a Friedel-Crafts alkylation reaction to form:

An aromatic compound of molecular formula $C_6H_4Br_2$ was nitrated,and three isomers of formula $C_6H_3Br_2NO_2$ were obtained. The original compound is:

How many products are capable of being formed from toluene in each of the following reactions shown in the figure?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The reaction is given as:Naphthalene + Oxalyl chloride $\xrightarrow{AlCl_3} [X]$ $\xrightarrow{Na-Hg, HCl \text{ (excess)}} [Y]$Product $Y$ is: